← Common Core coursesBMS 1110 · Applied Mathematics and Medical Biostatistics
BMS 1110 · Common Core (Tronc commun)Section 5.5 · Centre, spread and rates
Section 26 of 30

Rates, incidence and prevalence

Identify the numerator, denominator, time period and multiplier K of a rate, and calculate and interpret a mortality rate, a case-fatality rate, an incidence and a prevalence from a described situation.

New to this course? How each section works
  1. Learn gives you one short idea at a time. Each idea starts with a single sentence, then explains it, gives an example, and asks you a small question you can answer straight away.
  2. Explore shows a diagram of the same ideas. Click the numbered parts to read what each one is.
  3. Check asks a few questions. Answer them all correctly to finish the section and unlock the next one.
  4. “Go deeper” is optional. It adds mechanism and extra detail for when you are ready — nothing you need for the checks is hidden there.
Why this matters

Figures such as “250 deaths per 100,000 per year”, “incidence 2.5%” and “prevalence 20%” appear in every public-health report, ward audit and examination paper. They look alike and they are not alike: each counts a different event on top and divides it by a different population below. A nurse who cannot separate them will read a rising prevalence as a rising risk of catching a disease, or reassure a patient with a case-fatality figure that describes a different group of people altogether. This section gives you one habit that prevents all of those errors: before reading or calculating any frequency measure, name the numerator, the denominator, the time period and the multiplier.

What you need to know first

You need only arithmetic you already have: dividing one whole number by another and multiplying by 10, 100, 1,000 or 100,000. The single new idea is that the numerator and the denominator must describe the same population; everything else in this section is careful bookkeeping about which number belongs on which line.

Words to know (6)
Rate
A measure with an event counted on top, the population in which it occurred underneath, and a multiplier K that rescales the result to a readable size. 250 deaths in 100,000 people in a year, reported with K = 100,000, is a mortality rate of 250 per 100,000 per year.
Proportion
A part divided by the whole it came from. The numerator is always inside the denominator, so the value cannot pass 1, and the result carries no unit of its own. 160 people with diabetes among 2,000 surveyed give 160 ÷ 2,000 = 0.08, a proportion of 8%.
Multiplier (K)
The number the writer chooses to multiply the fraction by, so the result is easy to read. K changes the scale of the report, never the underlying frequency. The same fraction 0.0003 is 0.3 per 1,000 with K = 1,000, and 30 per 100,000 with K = 100,000.
Incidence
The number of new cases of a disease during a stated period, divided by the population still at risk at the start of that period. 50 new cases among 5,000 people at risk give an incidence of 50 ÷ 5,000 × 100 = 1% over the period.
Prevalence
The number of existing cases of a disease in a population at one point in time or over a stated period, divided by that whole population. 160 people currently with diabetes among 2,000 surveyed give a prevalence of 160 ÷ 2,000 × 100 = 8%.
Case-fatality rate
The deaths caused by a disease divided by the people who had that disease. It answers how lethal the disease is once contracted, not how common it is. 24 deaths among 300 diagnosed patients give a case-fatality rate of 24 ÷ 300 × 100 = 8%.
One idea at a timeIdea 1 / 7

In one sentence Morbidity measures illness or disease in a population; mortality measures death in that population.

Morbidity and mortality are the two families of frequency measure

Every frequency measure in this section belongs to one of two families. Morbidity covers illness: how much disease there is, who has it and who is developing it. Incidence and prevalence — the two measures you will meet most often — are both morbidity measures, because both count people who are ill. Mortality covers death: how many people died, and in which population. The mortality rate and the case-fatality rate are mortality measures. The two families are neither opposites nor partners: they do not move together. Better treatment can keep people alive with a disease, so morbidity rises while mortality falls; a severe epidemic can raise both at once. Whenever a figure is put in front of you, the first question is therefore not “how big is it?” but “which event was counted, illness or death?” The answer tells you whether you are reading a burden of disease or a count of deaths.

For example

A ward records 40 new chest infections during the month (morbidity) and two deaths among the patients who developed one (mortality). The two numbers describe different events in the same group of patients.

Pause and check yourself

A hospital reports that morbidity from a disease doubled while mortality from the same disease fell. Is that contradictory?

Show the answer

No. Morbidity and mortality count different events. More people can be diagnosed and living with the disease — because screening finds cases earlier or treatment keeps them alive — while fewer of them die. A rising morbidity with a falling mortality is exactly what a successful long-term treatment programme can produce.

Read detailed explanations
K is chosen, not given: how to read and compare rates

The multiplier K is the one part of a rate that is chosen rather than measured, and knowing that changes how you read every figure. K exists because the underlying fraction is usually a very small number: 0.005 is correct but unreadable, so the writer multiplies it by 100, 1,000, 100,000 or 1,000,000 to bring it into a comfortable range. The choice follows convention rather than arithmetic. Percentages (K = 100) suit short, familiar risks; per 1,000 suits hospital and birth statistics; per 100,000 is the convention for national mortality figures and for rare events; per 1,000,000 is reserved for very rare conditions. The supplied notes illustrate exactly this flexibility, and it is worth seeing that neither figure is a mistake. The mortality example uses K = 100,000: 250 deaths ÷ 100,000 population × 100,000 = 250 deaths per 100,000 per year. The incidence example uses K = 100: 50 new cases ÷ 5,000 people at risk × 100 = 1%. Both are arithmetically correct, and both would still be correct if the multipliers were swapped. What the notes leave implicit is the rule that makes figures comparable at all: before you compare or combine two rates, put them on the same K by multiplying or dividing by the ratio of the multipliers. To compare 250 per 100,000 with 1 per 100, multiply the second by 1,000, giving 1,000 per 100,000; the two now share a scale, although they still measure different events and must never be subtracted from each other. A final reporting rule follows: a rate without its K cannot be checked, and a rate whose denominator and period are missing cannot be checked either.

Person-time: the denominator when follow-up differs

Cumulative incidence assumes something that is often false: that every person in the denominator was observed for the whole period. Real patients arrive and leave. A patient admitted in March was not at risk during January; a patient discharged in June is not at risk in December; a patient who dies of another cause can no longer develop the disease. When follow-up differs from person to person, the honest denominator is not a head count but the total time each person spent under observation and still at risk. That quantity is called person-time, and its unit is the person-year, or the person-month or person-day for shorter studies. One patient followed for two years contributes two person-years; two patients followed for six months each contribute one person-year between them. The measure built on it is the incidence rate: incidence rate = new cases ÷ total person-time × K, with K usually 1,000, and the result read as cases per 1,000 person-years. Suppose a clinic follows 200 patients, 100 of them for a full year and 100 of them for six months each. The total person-time is 100 × 1 + 100 × 0.5 = 150 person-years. If six new cases appear, the incidence rate is 6 ÷ 150 = 0.04 per person-year, which is 40 per 1,000 person-years. Two precautions matter. First, stop counting a person’s time at the moment they leave, die or develop the disease, because after that moment they are no longer at risk. Second, never add a head count to person-time, or divide one by the other, without saying which quantity is underneath; the unit is the only evidence that the arithmetic was done on the right things.

Why incidence and prevalence differ, and what it means at the bedside

Prevalence is a snapshot of people currently living with a disease; incidence counts people becoming ill. Picture existing cases as water in a bath: new cases flow in, while recovery and death take cases out. Longer survival can increase prevalence even when the rate of new cases stays unchanged. This analogy explains the direction of change, but does not by itself calculate disease duration. The approximation prevalence ≈ incidence rate × average duration requires a stable situation and low prevalence, and uses a person-time incidence rate, not a one-year risk. The district’s 20% prevalence and 2.5% one-year risk do not establish an eight-year average duration. For planning, use prevalence to estimate ongoing care needs and incidence to understand new illness. Also check recovery, deaths and migration before explaining a change in prevalence.

Explore the diagram

Look at the whole drawing first. Then select one numbered part and connect it to the idea you just read.

Rates, incidence and prevalence

A four-panel teaching plate. The first panel gives the anatomy of every rate: the event counted, the population it occurred in, the time period and the chosen multiplier K, with the mortality example 250 ÷ 100,000 × 100,000 = 250 per 100,000 per year. The second lists four measures and the four different denominators they use. The third works one district of 5,000 adults where prevalence on 1 January is 20% but incidence during the year is only 2.5%, and explains why these two percentages cannot establish average disease duration. The fourth contrasts a proportion, which has no unit, with a strict rate, which carries a time period.

New to diagrams? Read this first
  1. Look at the whole drawing once without clicking anything. Ask yourself only: what kind of picture is this (a comparison, a route, a sequence, a table)?
  2. Press Play, or use the arrows, to move through the numbered parts in order. The drawing stays still; only the highlight moves.
  3. Click a number, or its name in the list below, to read what that part is and why it matters. Use “Hide labels” when you want to test your memory.
More controls
100%

01 / 4Numerator and denominator

Rates, incidence and prevalenceA four-panel teaching plate. The first panel gives the anatomy of every rate: the event counted, the population it occurred in, the time period and the chosen multiplier K, with the mortality example 250 ÷ 100,000 × 100,000 = 250 per 100,000 per year. The second lists four measures and the four different denominators they use. The third works one district of 5,000 adults where prevalence on 1 January is 20% but incidence during the year is only 2.5%, and explains why these two percentages cannot establish average disease duration. The fourth contrasts a proportion, which has no unit, with a strict rate, which carries a time period.Every measure: numerator ÷ denominator × K1. Event counted — the numerator2. Population it occurred in — the denominator3. Time period — always named4. K, chosen by the writer, always reported250 deaths ÷ 100,000 population × 100,000= 250 deaths per 100,000 per yearFour measures, four denominatorsMortality rate: deaths ÷ whole population × KRisk: new cases ÷ initially at-risk people × KPrevalence: existing cases ÷ population × 100Case-fatality: deaths ÷ people with the diseaseEvery one of them names its time period.One district: 5,000 adults, 1,000 already illPrevalence 1 Jan: 1,000 ÷ 5,000 × 100 = 20%At risk on 1 Jan: 5,000 − 1,000 = 4,000One-year risk: 100 ÷ 4,000 × 100 = 2.5%Prevalence 31 Dec: 1,100 ÷ 5,000 × 100 = 22%No recovery, deaths or migration assumed above.Proportion or rate? Check the structureProportion: numerator is part of denominatorIncidence rate: new cases ÷ person-time at risk160 ÷ 2,000 = 0.08 → 8%, no time unit40 ÷ 50,000 × 1,000 = 0.8 per 1,000 per year

If the drawing is wider than this panel, scroll it sideways. Labels stay readable; the numbered explanations below show the same ideas.

Numerator and denominator

The numerator is the event the writer chose to count — deaths, new cases or existing cases — and the denominator must be the population in which that event could have happened. Counting deaths in a city and dividing by the number of hospital beds produces a number with no meaning, because the two lines then describe different populations and the fraction cannot be interpreted.

Schematic teaching plate: the numbers are this section’s worked examples and do not describe a real district. Every rate on the plate states its multiplier K, because a rate without its K, its denominator and its period cannot be checked or compared.

Key points to remember

  • Morbidity measures illness and mortality measures death; incidence and prevalence are morbidity measures, while the mortality rate and case-fatality rate are mortality measures.
  • Every rate is (events ÷ population) × K, and K is chosen by the writer, never fixed by the data; a rate is meaningless without its denominator, its time period and its multiplier.
  • In a proportion the numerator is part of the denominator and the result has no unit; a strict rate carries a time unit such as person-years. The case-fatality rate is a proportion by structure.
  • Incidence = new cases ÷ population at risk at the beginning; people who already have the disease must be removed from the denominator, because they cannot become new cases.
  • Prevalence = existing cases ÷ whole population, at a point or over a period; it measures the burden of disease, and a high prevalence can coexist with a low incidence when the disease lasts a long time.
Go deeper

Worked example

Reading and calculating a rate with its full label. A district health office reports 45 maternal deaths during a year in which 9,000 live births took place. A colleague writes: “maternal mortality 0.5%”. Before accepting the figure, state which numbers belong in the numerator and the denominator, and write the rate in the published form.

  1. Name the event. The event counted is a maternal death, so 45 goes in the numerator.
  2. Name the population in which the events occurred. The deaths occurred among the 9,000 women who gave birth, so 9,000 is the denominator — not the district’s 30,000 women of reproductive age, many of whom did not give birth and were never at risk of a maternal death.
  3. Fix the time period. It is one year, and the period must appear in the written statement, because deaths accumulate with time.
  4. Choose K and write it down. Per 100,000 live births is the usual convention for this indicator, so K = 100,000.
  5. Calculate: 45 ÷ 9,000 = 0.005, then 0.005 × 100,000 = 500. State it in full: 500 maternal deaths per 100,000 live births per year. The colleague’s 0.5% is the same fraction with K = 100, since 0.005 × 100 = 0.5%. Both describe the same risk, but only the second form names the denominator and the period.

A rate is a full sentence, not a number. The numerator names the event, the denominator names the population that was actually exposed to it, the period names the time, and K says how many people the figure is reported per. The same fraction can honestly be written as 0.5% or as 500 per 100,000 per year; what must never happen is writing it without the denominator and the period.

Tutorial 1 — calculating and stating a mortality rate

A city reports 180 deaths from all causes during a calendar year. Its mid-year population is estimated at 300,000 people. Calculate the annual mortality rate with K = 1,000, and state the result in a form that a colleague could check.

Rule used: Mortality rate = deaths during the period ÷ the population during that period × K. The numerator is the number of deaths, the denominator is the whole population in which those deaths occurred, and K is the multiplier chosen by the writer and then reported; here K = 1,000, so the answer is read as deaths per 1,000 population per year.

  1. Write the general formula in words with its units before substituting any numbers.

    Reveal this step

    Mortality rate = deaths during the year ÷ population during the year × K, read as deaths per 1,000 population per year when K = 1,000.

  2. Which number is the numerator and which is the denominator? Why can nobody die twice, and what does that tell you about the size of the fraction?

    Reveal the answer

    180 deaths is the numerator and 300,000 people is the denominator. Each death is a different person, so the numerator counts distinct people and can never exceed the denominator. The fraction must therefore be smaller than 1, and usually very much smaller.

  3. Substitute the numbers into the formula, keeping the words “deaths” and “people” visible for now.

    Reveal this step

    Mortality rate = 180 deaths ÷ 300,000 people × 1,000.

  4. Carry out 180 ÷ 300,000 first, without the multiplier. Is the answer larger or smaller than 1, and why must it be?

    Reveal the answer

    180 ÷ 300,000 = 0.0006, a number far smaller than 1, because only 180 deaths occurred among 300,000 people. It must be smaller than 1 for the reason in the previous step: the numerator is a subset of the denominator.

  5. Now multiply by K = 1,000 and attach the unit to the answer.

    Reveal this step

    0.0006 × 1,000 = 0.6. The rate is 0.6 deaths per 1,000 population per year.

  6. State the rate in full, then say what would change if the writer had chosen K = 100,000 instead.

    Reveal the answer

    In full: 0.6 deaths per 1,000 population per year in that city. With K = 100,000 the same fraction is multiplied by 100,000 and gives 60 deaths per 100,000 population per year. The underlying risk is unchanged; only the reporting scale changes, which is why K must always be stated.

Answer: The annual mortality rate is 0.6 deaths per 1,000 population, which can equally be written 60 deaths per 100,000 population per year.

Keep this habit: Write the formula in words first, keep the numerator and the denominator in the same population, and finish the sentence with “per K per period”. A bare 0.6 is not a rate; 0.6 deaths per 1,000 people per year is a rate, because it can be checked.

Tutorial 2 — incidence and prevalence from one district

A district has 5,000 adults. On 1 January, 1,000 of them are already living with type 2 diabetes. During the year, 100 further adults are newly diagnosed, and nobody dies or leaves the district. Calculate the point prevalence on 1 January and the cumulative incidence during the year with K = 100, then explain why the two values are so different.

Rule used: Prevalence = existing cases ÷ the whole population × 100. Incidence = new cases during the period ÷ the population at risk at the beginning × 100. The prevalence denominator includes people who already have the disease; the incidence denominator must exclude them, because a person who is already ill is no longer at risk.

  1. Write the prevalence fraction for 1 January. Say which people go on top and which population goes underneath.

    Reveal this step

    The 1,000 people already living with diabetes go on top, because they have the disease on that date. The whole adult population of 5,000 goes underneath, because prevalence asks what share of everyone in the district is affected.

  2. Calculate the point prevalence on 1 January with K = 100.

    Reveal this step

    1,000 ÷ 5,000 = 0.20, then 0.20 × 100 = 20%. The point prevalence on 1 January is 20%.

  3. For the incidence, why is 5,000 the wrong denominator, and what is the right one?

    Reveal the answer

    The 1,000 people who already have diabetes cannot develop it again during the year, so they are not at risk and must not be counted. The population at risk at the beginning is 5,000 − 1,000 = 4,000, and that is the correct incidence denominator.

  4. Calculate the cumulative incidence for the year with K = 100.

    Reveal this step

    100 ÷ 4,000 = 0.025, then 0.025 × 100 = 2.5%. The cumulative incidence during the year is 2.5%.

  5. Prevalence is 20% and incidence is 2.5%. Why is prevalence so much larger, and what does the ratio 20 ÷ 2.5 = 8 estimate?

    Reveal the answer

    Prevalence counts every existing case, including the 1,000 people who have lived with diabetes for years, whereas incidence counts only the 100 diagnosed this year. The ratio 20% ÷ 2.5% = 8 estimates the average duration of the disease in years: a long-lasting disease accumulates cases, so a high prevalence can coexist with a low incidence.

  6. If nobody died and nobody was cured, what is the point prevalence on 31 December, and what does the change show?

    Reveal the answer

    Existing cases rise to 1,000 + 100 = 1,100, so prevalence = 1,100 ÷ 5,000 × 100 = 22%. Prevalence grew during the year by exactly the new cases, which is why prevalence measures the burden carried while incidence measures the flow of new disease.

Answer: Point prevalence on 1 January was 20%; cumulative incidence during the year was 2.5%; if nobody died or recovered, point prevalence on 31 December was 22%.

Keep this habit: Prevalence counts who has the disease now; incidence counts who became ill during the period. Their denominators differ, and because a long duration lets cases pile up, a high prevalence does not mean a high risk of catching the disease.

Now you try

Attempt each one on paper first. Write the formula, substitute the numbers, then check the unit of your answer.

  1. A city of 250,000 people records 1,200 deaths during one year. Calculate the annual mortality rate per 1,000 population and state it in full, naming the denominator and the period.

    Hint

    The denominator is the whole city population, not the number of patients in hospital. Divide first to get a fraction far below 1, then multiply by K = 1,000.

    Show the worked answer

    Mortality rate = 1,200 ÷ 250,000 × 1,000. First 1,200 ÷ 250,000 = 0.0048, then 0.0048 × 1,000 = 4.8. In full: 4.8 deaths per 1,000 population per year. The denominator is the 250,000 residents, all of whom could have died, and the period is one year. The same fraction with K = 100,000 would be 480 deaths per 100,000 population per year.

  2. In a village of 2,400 people, 60 people already have a disease on 1 January and 12 new cases occur during the year. Calculate the point prevalence on 1 January and the cumulative incidence over the year, using K = 100.

    Hint

    Prevalence keeps all 2,400 people underneath. For incidence, subtract the 60 existing cases from the population first, because those people are no longer at risk.

    Show the worked answer

    Prevalence = 60 ÷ 2,400 × 100 = 2.5%. The population at risk for incidence is 2,400 − 60 = 2,340, so incidence = 12 ÷ 2,340 × 100 = 0.51% over the year. Prevalence (2.5%) is much larger than incidence (0.51%) because it counts the 60 people who have had the disease for some time as well as the 12 new cases.

  3. A disease has an incidence of 4 new cases per 1,000 person-years and an average duration of 5 years. Using prevalence ≈ incidence × duration, estimate the prevalence and express it as a percentage.

    Hint

    Put both quantities on the same scale before multiplying: 4 per 1,000 is 0.004 per person-year. The duration is already in years, so the product is a pure fraction.

    Show the worked answer

    Write the incidence as a fraction: 4 ÷ 1,000 = 0.004 new cases per person-year. Multiply by the average duration: 0.004 × 5 = 0.02. As a percentage, 0.02 × 100 = 2%, which is 20 existing cases per 1,000 people. The estimate holds only for a stable population in which incidence is not changing quickly.

  4. In an outbreak, 20 people are diagnosed with a disease and 3 of them die. Elsewhere, a disease causes 500 deaths a year in a population of 2 million. Explain why the first figure is a case-fatality rate and the second a mortality rate, and calculate both.

    Hint

    Look at the denominator of each: the people who were diagnosed, or the whole population. For the second, choose K = 100,000 so the result reads as deaths per 100,000.

    Show the worked answer

    Case-fatality rate = 3 ÷ 20 × 100 = 15%, because the denominator is only the 20 patients who had the disease; it answers how lethal the disease is once contracted. Mortality rate = 500 ÷ 2,000,000 × 100,000 = 25 deaths per 100,000 population per year, because the denominator is the whole population; it answers how large a share of everyone died. The same disease can look terrifying in the first measure and small in the second when cases are rare.

Common misconception

Beginners often treat every frequency figure as a risk: if prevalence is 20%, they assume that one person in five will catch the disease this year. Prevalence counts people who already have the disease, including those diagnosed years ago, so it measures burden, not the chance of becoming ill. The chance of becoming ill is incidence, and it is calculated only among people who do not yet have the disease. A long-lasting disease can therefore show a high prevalence and a very low incidence at the same time.

Check your reasoning

A colleague reports that “the incidence of the disease fell from 5% to 2.5%, so fewer people have the disease now”. Explain what is wrong with the second half of that sentence, using the relationship between incidence, prevalence and duration.

Reveal an answer

Incidence measures only the flow of new cases; prevalence measures the stock of everyone who has the disease. A falling incidence reduces the number of new cases arriving, but the people already living with a long-lasting disease remain in the population and keep prevalence high for years. Prevalence can therefore stay level or even rise while incidence falls, for example when treatment extends survival. To claim that fewer people have the disease, the colleague must quote a prevalence, and to explain a change in prevalence both the incidence and the average duration of the disease must be examined.

Where this comes from

  • CDC: Morbidity frequency measures · Optional English reading; internet required. Checked 6 October 2026. Distinguishes incidence proportion, person-time incidence rate and prevalence.
  • BMS 1110 Applied Mathematics and Medical Biostatistics lecture notes (supplied) · Section 12, “Medical rates and frequencies”, lines 1159–1211 of the supplied notes (the rates block inside the extraction range 1028–1211): the list of common measures including case-fatality (1161–1166); morbidity as illness in a population, with the morbidity proportion and the note that the exact denominator and period must be specified (1167–1172); the mortality-rate formula with K = 1,000 or 100,000 (1173–1177) and the worked example 250 ÷ 100,000 × 100,000 = 250 deaths per 100,000 per year (1178–1181); incidence as new cases during a period among a population at risk (1182–1185) with the example 50 ÷ 5,000 × 100 = 1% (1186–1189); prevalence as existing cases at a point or over a period (1190–1192) with the example 160 ÷ 2,000 × 100 = 8% (1193–1196); the incidence-versus-prevalence comparison table (1197–1199).
  • BMS 1110 Applied Mathematics and Medical Biostatistics lecture notes (supplied) · The notes use K = 100,000 in the mortality example (line 1180) and silently switch to K = 100 in the incidence example (line 1188). Both results — 250 deaths per 100,000 per year and 1% — are arithmetically correct and are reproduced in this section without change; the missing rule that K is chosen by the writer and must be reported is supplied here and labelled as beyond the notes.
  • Beyond the supplied notes: the parts of a rate the notes leave implicit · The supplied notes give the formulas but not the rule that K is chosen and must be reported, the distinction between a proportion and a rate, person-time and the incidence rate with person-years as its denominator, the approximate relationship prevalence ≈ incidence × average duration, or the formula for the case-fatality rate that the notes list (line 1166) but never define. These are standard epidemiology taught here as beyond the notes; the worked figures from the notes are not altered.
  • Note on the course code · The supplied cover page reads “Course Number: BMS 110”. The curriculum catalogue in this project records “BMS 1110”; the catalogue is treated as authoritative and the notes’ cover value is retained here for provenance.

Lesson progress is saved on this device for the current learner. Practice answers stay separate and are not stored.

About this course and its sources

Bilingual lessons organised from the supplied BMS 1110 Applied Mathematics and Medical Biostatistics lecture notes (Mr. Ebangan Prosper Achuanoh). Diagrams are original educational schematics; sections that go beyond the supplied notes say so in their sources. Mathematics, clinical and French-language review are pending.