← Common Core coursesBMS 1110 · Applied Mathematics and Medical Biostatistics
BMS 1110 · Common Core (Tronc commun)Section 1.2 · Number foundations: algebra and fractions
Section 2 of 30

Order of operations and inequalities

Apply BODMAS to a real dosage expression, read the four inequality signs, solve a linear inequality and show its solution set on a number line.

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Why this matters

A dose calculation is not finished when the numbers are written down; it is finished when they have been combined in the agreed order. A nurse who divides before clearing a bracket can be out by a factor of ten, and a nurse who divides an inequality by a negative number without reversing the sign can read a safety range backwards. Both are arithmetic errors, both reach the patient, and both are prevented by two short rules that this section makes automatic.

What you need to know first

Bring the arithmetic from section 1.1: adding, subtracting, multiplying and dividing signed numbers, and reading a number line. Signed multiplication is not re-taught here. Take a pencil, because drawing the number line yourself is how an inequality answer becomes visible rather than remembered.

Words to know (5)
BODMAS
The agreed order for combining operations: Brackets, Orders, Division and Multiplication, Addition and Subtraction. Division and multiplication share one rank, and addition and subtraction share the other; each rank runs from left to right. In 5 + 3 × (12 − 8) ÷ 2 the bracket is cleared first, so the value is 11, not 16.
Inequality
A statement that compares two quantities which are not necessarily equal, using one of four signs: >, <, ≥ or ≤. Unlike an equation, it describes a whole range of values rather than a single one. Urine output below 30 mL/hr is written output < 30 mL/hr. It is true for 20 mL/hr, for 29 mL/hr and for every value under 30.
Linear inequality
An inequality in which the unknown appears only to the first power, so the highest power of the letter is one. Its solution is always a single ray on the number line. x + 4 > 7 is linear; its solution is x > 3. x² + 4 > 7 is not linear, because the letter is squared.
Solution set
All the values of the unknown that make the inequality true, collected into one group. Because there are usually infinitely many, we describe the group with a sign and a boundary rather than listing values. For t ≤ 20 hr, the solution set contains 20, 12, 0 and every negative hour; it excludes 21 and anything above it.
Endpoint (open or closed)
The boundary value of a solution set. An open endpoint, drawn as an empty circle, is excluded and belongs to < or >; a closed endpoint, drawn as a filled circle, is included and belongs to ≤ or ≥. x > 3 has an open circle at 3; x ≥ 3 has a filled circle at 3 and includes 3 itself.
One idea at a timeIdea 1 / 5

In one sentence Clear brackets first, then orders, then work division and multiplication from left to right, then addition and subtraction from left to right.

BODMAS gives one written expression one meaning

BODMAS is the agreed sequence for combining operations: Brackets, then Orders (powers and roots), then Division and Multiplication from left to right, then Addition and Subtraction from left to right. Division and multiplication share one rank, so you do them as they appear rather than division always first; addition and subtraction share the other rank. The convention exists so a written expression has exactly one value instead of one value per reader. Evaluate 2 + 3 × 4: the multiplication runs first, so 2 + 12 = 14, not 20. Evaluate 90 − 4 × (10 + 5) ÷ 2: the bracket gives 15, then 4 × 15 = 60, then 60 ÷ 2 = 30, then 90 − 30 = 60. In a dosage expression written (dose ÷ stock) × volume, the bracket tells every reader which division runs first.

For example

A ward order reads 120 ÷ (2 + 4) × 3 mg. The bracket gives 6, so 120 ÷ 6 = 20, then 20 × 3 = 60 mg. Multiplying the 6 and the 3 together first would give 120 ÷ (6 × 3) = 6.7 mg instead, which is why the bracket is cleared before the shared rank is worked.

Pause and check yourself

A colleague evaluates 40 − 8 ÷ 2 by subtracting first and announces 16. Is that correct, and what is the right value?

Show the answer

No. Division outranks subtraction in BODMAS, so 8 ÷ 2 = 4 and 40 − 4 = 36. The colleague’s 16 comes from 40 − 8 = 32, then 32 ÷ 2, which reverses the agreed order and divides the wrong quantity.

Read detailed explanations
Why a negative multiplier flips the order

The reversal rule feels arbitrary until you watch it happen on the number line. Start with 2 < 5. The point 2 sits four units to the left of the point 5. Multiplying every number by −1 reflects the whole line through zero, like a mirror standing at the origin: each point jumps to the opposite side, and its distance from zero is unchanged. Reflection is order-reversing, so the image of 2, which is −2, now lies to the right of the image of 5, which is −5. Reading the picture gives −2 > −5. Nothing about arithmetic was assumed; the geometry forced the conclusion. The same reasoning separates the two families of operations. Adding a fixed number slides both points by the same amount, so their relative positions never change: addition is order-preserving. Multiplying by a positive number stretches the line by a constant factor, which also preserves the relative positions. Multiplying by a negative number reflects and therefore reverses them. Dividing by −4 is nothing more than multiplying by the negative reciprocal −1/4, which is why the rule mentions divisors as well as factors. The size of the negative number is irrelevant; only its sign drives the reversal. A useful consequence is that an inequality may be multiplied or divided by any positive quantity as often as you like, and by a negative quantity only if you flip the sign in the same line.

Compound inequalities, intervals and clinical reference ranges

A compound inequality traps the unknown between two limits, as in 19 ≤ 5(x + 2) ≤ 25. Treat it as three members that must all be changed in the same way, exactly as if a single balance had three pans. Clear the bracket first: 5(x + 2) = 5x + 10, so 19 ≤ 5x + 10 ≤ 25. Subtract 10 from each of the three members: 9 ≤ 5x ≤ 15. Divide each member by 5, a positive number, so both signs keep their direction: 1.8 ≤ x ≤ 3. The same answer in interval notation is [1.8, 3]; square brackets mark endpoints that are included, round brackets mark endpoints that are excluded. Half-open intervals combine the two, for example (0, 24] meaning more than zero but at most 24. One trap belongs with the reversal rule: if a negative number ever multiplies or divides a compound inequality, both signs flip and the two outer values appear to swap places, so the smallest number must be written on the left again before you read the answer. Clinical reference ranges are compound inequalities in disguise. A potassium reference interval of 3.5–5.0 mmol/L means 3.5 ≤ K ≤ 5.0, and a result inside the interval is unremarkable while one outside it triggers review. Monitors take the same structure further with alarm limits and a therapeutic window, the band between a trough level that is too low to work and a peak level that is toxic, so an infusion is titrated towards the middle rather than the edges. Reading a two-sided range as one inequality, rather than as two separate problems, is what makes the alarm settings on a pump look obvious instead of mysterious.

Precedence is a safety device, not a formality

In dosage arithmetic the danger is rarely a large number; it is a misplaced priority. Consider one expression with two possible readings. With an ordered dose of 750 mg, a stock strength of 500 mg and a stock volume of 5 mL, the intended calculation is (750 ÷ 500) × 5 = 1.5 × 5 = 7.5 mL. If a reader instead groups the stock as 500 × 5 = 2,500 mg and divides, the calculation becomes 750 ÷ 2,500 = 0.3 mL, twenty-five times smaller. The arithmetic on each line is flawless; only the precedence differs. Because precedence is fixed by agreement rather than by context, the bracket is the only thing that records which grouping the prescriber and the pharmacist intended, which is why rewriting or dropping a colleague’s bracket is never a harmless tidy-up. Three habits convert precedence from a rule into a safeguard. First, write the substituted expression with its brackets before calculating, so the intended grouping exists on paper and can be examined. Second, carry the unit on every line: a wrong precedence usually reveals itself as a wrong unit, milligrams appearing where millilitres should be, or a volume smaller than a measurable draw. Third, have a second nurse reproduce the calculation independently from the order rather than check your written lines, because two people reading the same slip of paper tend to repeat the same misreading. A fourth habit belongs to documentation: transcription is where brackets disappear. Copying an order into a chart is a fresh reading, and a dropped pair of brackets at that moment can turn a safe volume into a tenfold error that no arithmetic step will flag.

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BODMAS in dosage expressions and the two rules of inequalities

Three teaching panels. The first gives the BODMAS order with three fully evaluated expressions, including the dosage expression (750 ÷ 500) × 5 = 7.5 mL. The second lists the four inequality signs with a clinical reading of each. The third states the two solving rules and shows 100 − 4t ≥ 20 solved to t ≤ 20 on a number line with a filled circle at 20.

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01 / 5The BODMAS order and two evaluations

BODMAS in dosage expressions and the two rules of inequalitiesThree teaching panels. The first gives the BODMAS order with three fully evaluated expressions, including the dosage expression (750 ÷ 500) × 5 = 7.5 mL. The second lists the four inequality signs with a clinical reading of each. The third states the two solving rules and shows 100 − 4t ≥ 20 solved to t ≤ 20 on a number line with a filled circle at 20.BODMAS: B → O → D and M → A and SSame rank: work left to right.2 + 3 × 4 = 2 + 12 = 1490 − 4 × (10 + 5) ÷ 2= 90 − 4 × 15 ÷ 2 = 90 − 60 ÷ 2= 90 − 30 = 60Dosage: (dose ÷ stock) × volume, in mL(750 ÷ 500) × 5 = 1.5 × 5 = 7.5 mLOne 500 mg / 5 mL ampoule holds only 5 mL → two ampoules.The four inequality signs> greater than 38.6 °C > 38.0 °C< less than urine output < 30 mL/hr≥ greater or equal rate ≥ 50 beats/min≤ less or equal single dose ≤ 500 mgTwo rules for solving inequalities1. Add or subtract the same on both sides.x + 4 > 7 → x > 7 − 4 → x > 32. × or ÷ by a negative reverses the sign.100 − 4t ≥ 20 → −4t ≥ −80 → t ≤ 20010203040t ≤ 20 hr: filled circle at 20 marks that 20 hr is included.

If the drawing is wider than this panel, scroll it sideways. Labels stay readable; the numbered explanations below show the same ideas.

The BODMAS order and two evaluations

Brackets come first, then orders, then division and multiplication together from left to right, then addition and subtraction together from left to right. The first line shows why the order matters: 2 + 3 × 4 is 14, because the multiplication runs before the addition. The second evaluation clears the bracket (10 + 5 = 15), then works the shared rank left to right (4 × 15 = 60, then 60 ÷ 2 = 30), and finishes with the subtraction 90 − 30 = 60.

Teaching schematic drawn to a regular tick scale of 10 hours per division; the number line is a guide to direction and to open versus filled endpoints, not a measurement instrument.

Key points to remember

  • BODMAS: brackets first, then orders, then division and multiplication from left to right, then addition and subtraction from left to right.
  • The open end of an inequality sign faces the larger quantity; ≥ and ≤ include their boundary, > and < do not.
  • A linear inequality has the unknown to the power one; a term crossing the sign changes its operation, so +4 becomes −4.
  • Multiplying or dividing both sides by a negative number reverses the sign: 16 ≥ −4x becomes x ≥ −4.
  • Draw the answer as a ray: open circle for < or >, filled circle for ≤ or ≥, then test one value inside and one outside.
Go deeper

Worked example

Evaluating an infusion-rate expression in order. A ward uses the expression 500 ÷ (4 + 6) × 2 to estimate an infusion rate in mL/hr, where 500 mL is the volume to be given, 4 + 6 is the number of hours split into two blocks, and 2 is a doubling factor for a second line. The nurse must evaluate it without changing a single bracket.

  1. Read the expression and name the first rank present. Brackets come first, so the only bracket, (4 + 6), is the first move.
  2. Evaluate the bracket: 4 + 6 = 10. The expression is now 500 ÷ 10 × 2.
  3. There are no orders, so move to the shared rank of division and multiplication and work it from left to right. Division comes first here because it is written first: 500 ÷ 10 = 50.
  4. Continue the same rank: 50 × 2 = 100. There is no addition or subtraction left to do.
  5. Attach the unit and test the result for sense. The answer is 100 mL/hr. If the bracket had been moved to 500 ÷ (10 × 2), the rate would be 25 mL/hr, four times slower, so the bracket is checked, not assumed.

Evaluating in order means naming the rank out loud before each move: bracket, then the shared division-and-multiplication rank from left to right, then the shared addition-and-subtraction rank. Twenty extra seconds of working, written line by line with units, is what makes the answer reproducible by the nurse checking behind you.

Tutorial 1 — evaluating a dosage expression with brackets

A stock ampoule contains 500 mg of a drug in 5 mL. The order is for 750 mg. The ward writes the volume to draw up as (750 ÷ 500) × 5 mL. Evaluate that expression move by move and decide whether the volume can be drawn from a single ampoule.

Rule used: BODMAS: clear the bracket first, then work division and multiplication from left to right, then addition and subtraction from left to right. The bracket protects the division (ordered dose ÷ stock dose), and the volume in millilitres that contains the stock dose multiplies it.

  1. Identify the ordered dose, the stock dose and the volume that holds the stock dose, then write them into the expression before calculating anything.

    Reveal this step

    Ordered dose = 750 mg. Stock dose = 500 mg, and that 500 mg sits in 5 mL. Substituted into the rule, the expression is (750 ÷ 500) × 5 mL, and no arithmetic has been done yet.

  2. Why does the bracket matter here, and what could a tired reader do with 750 ÷ 500 × 5 if the bracket were dropped?

    Reveal the answer

    The bracket forces the division to be finished first and removes any doubt about the intended grouping. Without it, a tired reader may treat the line as 750 ÷ (500 × 5) = 750 ÷ 2,500 = 0.3 mL, which is twenty-five times too small. The bracket is what makes the intended meaning survive being read quickly.

  3. Clear the bracket: divide the ordered dose by the stock dose and write the quotient.

    Reveal this step

    750 ÷ 500 = 1.5. The expression is now 1.5 × 5 mL. The quotient 1.5 is a pure ratio, so it carries no unit of its own.

  4. The quotient is 1.5. One and a half of what, and what unit will the finished answer carry?

    Reveal the answer

    1.5 means the ordered dose is one and a half times the stock dose, so it is a number of stock doses with no unit. Multiplying by the 5 mL that contains one stock dose gives millilitres: 1.5 × 5 = 7.5 mL, a volume a syringe can measure.

  5. Multiply and compare the answer with the volume of one ampoule.

    Reveal this step

    1.5 × 5 = 7.5, so the volume is 7.5 mL. One ampoule holds only 5 mL, so 7.5 mL needs two ampoules — or a different stock strength. The arithmetic is correct and the order must be queried before administration.

Answer: (750 ÷ 500) × 5 = 7.5 mL. This exceeds the 5 mL in one 500 mg ampoule, so the order cannot be met from a single ampoule.

Keep this habit: Write the substituted expression with its bracket before doing any arithmetic, clear the bracket first, and read the answer back against the container you actually have. The number and the volume check are two separate safety steps, and both belong in the record.

Tutorial 2 — solving a linear inequality and checking it

After an infusion is stopped, a patient’s estimated plasma level is written as 100 − 4t, where t is the number of hours since the infusion stopped. The level must stay at or above 20 units. Find the values of t for which the treatment remains effective, and check your answer by substitution.

Rule used: For a linear inequality, do the same operation to both sides. A term that crosses the inequality sign changes its operation, so +4 becomes −4 and vice versa. Multiplying or dividing both sides by a negative number reverses the sign: ≥ becomes ≤.

  1. Write the requirement as an inequality and move the +100 across the sign.

    Reveal this step

    The requirement is 100 − 4t ≥ 20. The +100 crosses the sign and becomes −100: −4t ≥ 20 − 100, so −4t ≥ −80. The sign is still ≥, because only a term crossed and nothing has been multiplied or divided yet.

  2. The coefficient of t is now −4. What must happen to the sign of the inequality when you divide both sides by it, and why?

    Reveal the answer

    The sign must reverse, from ≥ to ≤. Dividing by −4 is the same as multiplying by the negative reciprocal −1/4, and multiplying by a negative reflects both sides of the inequality on the number line, so the order of the two sides swaps. The rule is not optional: skipping the reversal produces exactly the wrong half of the line.

  3. Divide both sides by −4, reversing the sign, and write the solution.

    Reveal this step

    −4t ≥ −80 becomes t ≤ (−80) ÷ (−4), so t ≤ 20. The reversal is what makes the inequality read the right way round; the arithmetic of the division itself gives a positive 20.

  4. Check the answer by substituting t = 10 and then t = 25 into the original inequality 100 − 4t ≥ 20. What does each value tell you?

    Reveal the answer

    For t = 10: 100 − 40 = 60, and 60 ≥ 20 is true, so 10 belongs to the solution set as t ≤ 20 predicts. For t = 25: 100 − 100 = 0, and 0 ≥ 20 is false, so 25 is correctly excluded. One accepted value and one rejected value together confirm both the number and the direction.

  5. Draw the solution set on a number line and say what the picture means in clinical words.

    Reveal this step

    Put a filled circle at 20, because 20 is included by ≤, and shade the ray to the left. Clinically, the treatment stays effective for any time up to and including 20 hours after the infusion stops; beyond 20 hours the level falls below 20 and the patient is no longer covered.

Answer: 100 − 4t ≥ 20 gives t ≤ 20 hr, drawn as a filled circle at 20 with the ray shaded to the left. The treatment remains effective for at most 20 hours.

Keep this habit: Move terms across the sign first, then deal with the coefficient. If the coefficient is negative, reverse the sign at that moment, and never later. Finish by substituting one value that should work and one that should not; the excluded value is the one that catches a forgotten reversal.

Now you try

Attempt each one on paper first. Write the formula, substitute the numbers, then check the unit of your answer.

  1. Evaluate 8 + 4 × (15 − 9) ÷ 3, writing each line separately and naming the BODMAS rank you used at every step.

    Hint

    Brackets first, then the shared division-and-multiplication rank from left to right, and keep the addition for the very last line.

    Show the worked answer

    15 − 9 = 6 (brackets). Then 4 × 6 = 24 (multiplication). Then 24 ÷ 3 = 8 (division). Finally 8 + 8 = 16 (addition). The value is 16. Adding first would give 12 × 6 ÷ 3 = 24, so the rank order changes the answer by eight units.

  2. A temperature chart reads 38.6 °C and the ward’s fever threshold is 38.0 °C. Write the comparison with an inequality sign, then explain what would change if the sign were ≥ instead.

    Hint

    The open end of the sign faces the larger quantity. Decide whether the threshold value itself should count before choosing between > and ≥.

    Show the worked answer

    38.6 °C > 38.0 °C, read as 38.6 is greater than 38.0, so this patient has a fever. With ≥ the statement 38.6 ≥ 38.0 would still be true, but the meaning at the boundary would change: ≥ would count a reading of exactly 38.0 °C as a fever, whereas > leaves 38.0 °C outside the definition.

  3. Solve 5x + 3 ≤ 28, draw the solution set on a number line, and check the answer by substituting x = 4 and x = 6.

    Hint

    Move the +3 across the sign, where it becomes −3, then divide by the positive coefficient 5, which does not reverse the sign.

    Show the worked answer

    5x + 3 ≤ 28 becomes 5x ≤ 28 − 3 = 25, then x ≤ 5. Draw a filled circle at 5 with the ray shaded to the left, because 5 itself is included. Checking: x = 4 gives 5 × 4 + 3 = 23, and 23 ≤ 28 is true; x = 6 gives 33, and 33 ≤ 28 is false, so 6 is correctly outside the ray.

  4. Solve the three-part inequality 19 ≤ 5(x + 2) ≤ 25, then check the answer by substituting x = 2 and describing the solution set on a number line.

    Hint

    Do the same thing to all three parts: clear the bracket, subtract 10 from each part, then divide each part by 5, which is positive.

    Show the worked answer

    5(x + 2) = 5x + 10, so 19 ≤ 5x + 10 ≤ 25. Subtract 10 from all three parts: 9 ≤ 5x ≤ 15. Divide all three by the positive 5, so neither sign reverses: 1.8 ≤ x ≤ 3. On the number line that is a segment from 1.8 to 3 with a filled circle at each end, because both boundaries are included. Checking x = 2 gives 5(4) = 20, and 19 ≤ 20 ≤ 25 is true.

Common misconception

Beginners often treat the inequality sign as part of the decoration and carry it through every step unchanged. That works for adding and subtracting, which is why the habit forms, but it fails the moment a negative number multiplies or divides. Two negatives actually invert the order of the two sides, so −2 < 5 becomes 2 > −5. The safe habit is to ask one question before every multiplication or division: is this number negative? If it is, reverse the sign on that same line, and confirm the result by substituting one value the answer should exclude.

Check your reasoning

Explain in your own words why the rule “a term crossing the inequality sign changes its operation” and the rule “multiplying or dividing by a negative reverses the sign” are two different rules that must not be mixed up.

Reveal an answer

The crossing rule is only a shortcut for adding or subtracting the same quantity on both sides, and adding or subtracting never changes the order of two numbers, so the sign survives untouched. The reversal rule is about multiplication and division: multiplying by a negative reflects both sides on the number line, so the left-right order swaps and the sign must follow. Crossing a term moves it by addition; the reversal happens only when a negative factor acts on both sides. Mixing them up produces either a sign reversed for no reason or a sign left unchanged when it had to flip.

Where this comes from

  • BMS 1110 Applied Mathematics and Medical Biostatistics lecture notes (supplied) · Unit One, lines 58–83: BODMAS and its six ranks; the four inequality signs >, <, ≤ and ≥; the definition of a linear inequality with the example x + 4 > 7; the crossing rule; the reversal rule when the coefficient of the unknown is negative; the practice inequalities 3x − 2 > 1/2, 16 ≥ −4x and 19 ≤ 5(x + 2) ≤ 25.
  • Note on the course code · The supplied cover page reads “Course Number: BMS 110”. The curriculum catalogue in this project records “BMS 1110”; the catalogue is treated as authoritative and the notes’ cover value is retained here for provenance only.
  • Beyond the supplied notes: the geometry of the reversal and clinical ranges · The supplied notes give BODMAS with no worked arithmetic, so the dosage evaluations, the three fully worked examples, the number-line convention for open and closed endpoints, interval notation, and the reflection argument for why a negative multiplier reverses the order are standard algebra supplied here and labelled as beyond the notes.

Lesson progress is saved on this device for the current learner. Practice answers stay separate and are not stored.

About this course and its sources

Bilingual lessons organised from the supplied BMS 1110 Applied Mathematics and Medical Biostatistics lecture notes (Mr. Ebangan Prosper Achuanoh). Diagrams are original educational schematics; sections that go beyond the supplied notes say so in their sources. Mathematics, clinical and French-language review are pending.